Math, asked by yogeshkumarg394, 14 hours ago

Divide 60 into 3 parts such that the third part is 10 more than secand and the secand part is 10 than the first​

Answers

Answered by SRINITHYA9A
0

Heyyy! Here is ur answer-
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Let

Second part = x

Third part = x + 10

First part= x-10


Adding

x + (x+10) + (x-10) = 60

3x = 60

x=20


So,

First part = x-10 = 10

Second part = x = 20

Third part = x+10 = 30


Hence the numbers which make 60 are- 10, 20 and 30

Answered by roysen1992
0

Answer:

10 20 30

Step-by-step explanation:

Let 1st part is x

second part is x + 10

Therefore the third part = x + 10 + 10 = x +20

x + x + 10 + x + 20

3x + 30 = 60

3x = 60-30

3x = 30

x = 10

Therefore 1st person will get 10

second one will get 10+10 = 20

Third will get 10+20 = 30

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