Math, asked by saikrishna8604, 1 year ago

Divide 60 into three parts such that first will be 3/4 of second and the second will be 4/5of the third.

Answers

Answered by MansiGarg1111
10
Heya...
Here is your answer --

Let the third part be x
Second part = 4x/5
First part = 3/4 × 4x/5 = 3x/5

ATQ
x+4x/5+3x/5 = 60
5x+4x+3x/5 = 60
12x/5 = 60
12x = 60×5
x = 60×5/12
x = 5×5
x = 25

Third part = x = 25
Second part = 4x/5 = 4/5×25 = 20.
First part = 3x/5 = 3/5×25 = 15

HOPE IT HELPS...!!
Answered by Anushkasampa123
6

Hello friend!!
Here is your answer --

Let the third part be x.
Second part = 4x/5
First part = 3/4 × 4x/5
= 3x/5

x+4x/5+3x/5 = 60
5x+4x+3x/5 = 60
12x/5 = 60
12x = 60×5
x = 60×5/12
x = 5×5
x = 25

Third part :
x = 25
Second part :
4x/5
= 4/5×25 = 20.
First part :
= 3x/5
= 3/5×25 = 15

Hope it helps!!☺
Thanks!!☺
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