Question

Divide 60 into two equal parts, such that e times the smaller part may exceed 100 by as much as 9 times the bigger falls short of 200

Answer 1

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Let the first part be x

And the second part be (60-x)

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$3(60 - x) - 100 = 200 - 9(x) \\ \\ = > 180 - 3x - 100 = 200 - 9x \\ \\ = > - 3x + 9x = 200 + 100 - 180 \\ \\ = > 6x = 120 \\ \\ = > x = \frac{120}{6} \\ \\ = > x = 20$

First part is 20

Second part is (60-x) = 60 - 20 = 40

$\large{\boxed{\bold{Hope\:it\:helps\:you!}}}$

Answer 2

3(60 - x) - 100 = 200 - 9(x)
180 - 3x - 100 = 200 - 9x
- 3x =9x = 200 + 100 - 180
6x = 120
x = 120/6 
x = 20

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