Math, asked by bvamtayaru82, 6 months ago

Divide 60 into two parts, so that three times the greater may exceeds 100 by as much as 8 times
the less falls shot of 200.
what is the greater part?

A)24
B)36

dont tell the option only please explain question very very clearly

I will give 20 points and brainlist answer

if any post waste answers I will report their question and block their account

so plz fast

Answers

Answered by freedarajesh2003
0

Answer:

Step-by-step explanation:

ANSWER

Let larger part be x  

then smaller part will be 60−x

Now,  According to question

3(60−x)=100+(200−9x)

⇒180−3x=100+200−9x

⇒6x=300−180

⇒6x=120

⇒x=20 and 60−x=60−20=40

So, the two parts of 60 satisfying given condition are 20 and 40.

Answered by tennetiraj86
1

Answer:

The greater part is 36

Step-by-step explanation:

Given that:-

Let the greater part be X

and The smaller part be Y

Their sum =60

=>X+Y=60

Y=60-X

smaller part =60-X.....(1)

now three times of greater part =3(X)=3X

8 times the smallerpart=8(60-X)=>480-8X....(2)

Now according to the problem

three times the greater may exceeds 100 by as much as 8 times

times the greater may exceeds 100 by as much as 8 timesthe less falls shot of 200.

=>3X=100+200-480+8X

=>3X=300-480+8X

=>3X=-180+8X

=>3X-8X=-180

=>-5X=-180

=>X=-180/-5

=>X=36

The greater part =36

The smaller part=60-36=24

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