Question

Divide 60 into two parts such that 3 times the smaller part may exceed 100 by as much as 9 times the bigger falls short of 200

Answer 1

Question -

Divide 60 into two parts such that 3 times the smaller part may exceed 100 by as much as 9 times the bigger falls short of 200.

Solution -

Let the two parts be x and ( 60 - x ) respectively .

Here x is the smaller part and ( 60 - x ) is the larger part.

Now, according to the question,

100 - 3x = 200 - 9 ( 60 - x )

100 - 3x = 200 - 540  +  9x

12x = 640 - 200 = 440

x = 36.67 approximately .

So, the parts are 36.67 and 23.33 respectively .

Answer 2

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