Question

Divide 60 into two parts such that 3 times the smaller part may exceed 100 by as much as 9 times the bigger falls short of 200?

Answer 1

Step-by-step explanation:

SIKE!!!

Answer 2

Answer:

let smaller no = x greater no = y

3x - 100 = 200-9y

9y + 3x = 300

Given, x + y = 60

Now we've got 2 equations.

3x + 9y = 300

x + y = 60

multiply eq 2 with 3 and subtract the 2.

3x+9y=300

- 3x+3y= 180

= 6y = 120

y =20

x+y = 60

x +20= 60

x = 40