Question

divide 60 into two parts such that 3 times the smaller part may exceed 100 by as much as 9 times the biggest Falls short of 200

Answer 1

Let the smaller part be x and biggest part be y.

Now according to the question,

x+y=60

x = 60 -y ---------------(1)

and

3x+100 = 9y-200

3x-9y=-300

x-3y=-100 ----------- (2)

from equation (1)

60-y-3y=-100

60-4y=-100

15-y=-25

y = 40

x = 20