Question

Divide 60 into two parts such that 3 times the smaller part may be exceed 100 by as much as 9 times the bigger Falls short of 200

Answer 1

$\bold{\underline{Solution:}}$

Let the one part be x.

And the other part be (60 - x).

$\bold{\boxed{A.T.Q}}$

3(60 - x) - 100 = 200 - 9x

=> 180 - 3x - 100 = 200 - 9x

=> 80 - 3x = 200 - 9x

=> -3x + 9x = 200 - 80

=> 6x = 120

=> x = $\frac{120}{6}$

=> x = 20

So,

The first part = 20

And the second part = (60 - 20) = 40
______________

$\textbf{Thank you!!}$

Answer 2

Hay dear friend

if we let the one part be x then second part be (60-x) Then,

3(60-x)-100=200-9x
80-3x = 200-9x
6x = 120
x = 20

now the first part be 20 and second part be 60-20 = 40

I hope it's help you

Regards : @swarnimkumar21##