Question

divide 60 into two parts, such that 3 times the smaller part may exceed 100 by as much as 9 times the bigger falls short of 200

Answer 1

let the two part be x and y, x be smaller and y be bigger.
now as per given data
x+y=60

3x-100=200-9y

from above two equations we get two parts as 40 and 20