Question

divide 600 2 parts such that 40% of one exceed 60% of other by 120​

Answer 1

Step-by-step explanation:

Let the first part be x

the the second part will be  600 - x  

now the equation will be 

40% of x exceeds 60% of (600-x) by 120

40/100 into x +120 = 60/100 into (600-x)

40x/100 + 120 = 36000/100 - 60x/100

40x/100 + 60x/100 = 360 - 120 

100x/100 = 240

x = 240 

so, one part is 240 and other is 360

Answer 2

Step-by-step explanation:

let the two parts be x,y

then (40/100)x = (60/100)y + 120

(2/5)x = (3/5)y + 120

2x = 3y +(120x5)

x = (3/2)y + 300

WKT. x + y = 600

y+ ((3/2)y +300) = 600

(5/2)y = 300

y = 120

x = 600-120 = 480