Question

Divide 600 among A,B and C in such a way that A receives twice as much as B, who gets three times as much as C

Answer 1

Answer:

Step-by-step explanation:

A = 2x of B

B = 3x of C

A + B + C  = 600

2x + 3x + x = 600

6x = 600

x = 100 I think

Answer 2

Answer:

A received 360, B received 180 and C received 60.

Step-by-step explanation:

Given,

  600 divided among A,B and C.

               A + B + C = 600                                 equation (1)

  A receives twice as much as B.

  i.e.           A = 2B

 and B receives three times as much as C.

  i.e.           B = 3C

 we need to find the values of A, B and C.

Sol:  We have,

               A + B + C = 600

        we know, A = 2B

                 ∴      A = 2(3C)                              ∵ B = 3C

                         A = 6C

         on putting the values of A and B in equation (1), we get

                         6C + 3C + C = 600

                                       10C = 600

                                     ∴    C = 60

     Therefore, B = 3 x 60 = 180

               and, A = 6 x 60 = 360

Thus, A received 360, B received 180 and C received 60.