Math, asked by RompritaiSej, 1 year ago

Divide 600 in two parts such that 40% of one exceeds 60% of the other by 120.

Answers

Answered by neelimashorewala

125

Let the first part be x
the the second part will be 600 - x
now the equation will be
40% of x exceeds 60% of (600-x) by 120
40/100 into x +120 = 60/100 into (600-x)
40x/100 + 120 = 36000/100 - 60x/100
40x/100 + 60x/100 = 360 - 120
100x/100 = 240
x = 240

so, one part is 240 and other is 360

Golda: Your answer is wrong because if you cross check the answer the one part which is 240 and the other part which is 360 will not give you right answer. 40 % of 240 = 60 % of 360 + 120

Golda: 40 % of 240 = 96, 60 % of 360 = 216

Golda: 96 = 216 + 120 . L.H.S. is not equal to R.H.S.

neelimashorewala: oh i am so sorry...i mistakenly added 120 on wrong side...my mistake.

Answered by Golda

125

Solution:-
Let the one part be 'x' and the other part be 600 - x
Therefore, according to the question.
(x × 40)/100 = {(600 - x) × 60}/100 + 120
On solving both L.H.S. and R.H.S. we get
2x/5 = {(600 - x)3}/5 + 120
2x/5 = (1800 - 3x)/5 + 120
Taking L.C.M of (1800 - 3x)/5 + 120/1, and solving it, we get
2x/5 = (1800 - 3x + 600)/5
2x + 3x = 1800 + 600
5x = 2400
x = 2400/5
x = 480
Therefore the first part is 480 and the other is 600 - 480 = 120
Answer.

Let us cross check the answer.
1st part = 480 and 2nd part = 120
40 % of the first part exceeds 60 % of the other by 120.
40 % of 480 = 60 % of 120 + 120
192 = 72 + 120
192 = 192
L.H.S. = R.H.S.
Hence proved.

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