Question

Divide 600 into 2 part s such that40% of one exceeds 60% of other by 120

Answer 1

Answer:

Let, the two parts be x and y

B/Q

$\frac{40}{100} x = \frac{60}{100} y + 120$

=> x = (60/100y + 120) 100/40

$= > \: x = \: \frac{100}{40} \times \frac{60}{100} y + \frac{100}{40} \times 120$

$= > x = \frac{3}{2} y + 300$

.

Now,

x + y = 600

=> 3/2 y + 300 + y = 600

$= > \frac{3}{2} y + y = 600 - 300$

$= > \frac{5y}{2} = 300$

=> 5y = 600

=> y = 120

.

So,

$= > x = \frac{3}{2} y + 300$

$= > x = \frac{3}{2} \times 120 + 300$

$= > x = 180 + 300 = 480$

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Hope this helps :)