Question

divide 62 into two parts such that one fourth part of the first and 2/5 part of the second are in the ratio 2 ratio 3 find the first part

Answer 1

Let x and y be the reqd parts
Then x+y=62-----------(1)
Also(x/4)÷(2y/5)=2÷3
3x/4=4y/5
15x-16y=0-------------------(2)
15eq(1)-eq(2)
15x+15y-15x+16y=930
31y=930
y=30
So x=32

Answer 2

Answer:

The first part is 32

Step-by-step explanation:

Given the number 62

we have to divide 62 into two parts such that one fourth part of the first and 2/5 part of the second are in the ratio 2:3

Let the first part is x then other part is 62-x

$\frac{1}{4}x:\frac{2}{5}(62-x)=2:3$

$\frac{\frac{1}{4}x}{\frac{2}{5}(62-x)}=\frac{2}{3}$

$\frac{x}{62-x}=\frac{16}{15}$

$15x=992-16x$

Adding 16x on both sides, we get

$31x=992$

Divide throughout by 31, we get

$x=\frac{992}{31}=32$

Hence the first part is 32