Divide 62 into two parts such that one fourth part of the first and two fifth part of second are in the ratio 2:3. Find the value of first part
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Let it divide in x
so other part= 216000-x
ATQ
x/4= 1/5(216000-x )
x/4=43200-x/5
x/4+x/5 =43200
9x/20=43200
x=43200×20/9= 96000=FIRST PART
SECOND PART=216000-96000120000
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so other part= 216000-x
ATQ
x/4= 1/5(216000-x )
x/4=43200-x/5
x/4+x/5 =43200
9x/20=43200
x=43200×20/9= 96000=FIRST PART
SECOND PART=216000-96000120000
PLEASE SELECT MY ANSWERS AS BRAINLIEST
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