Question

Divide 63(p4 + 5p3 - 24p2) by 9p(p + 8).​

Answer 1

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Answer 2

The quotient is 7p(p-3)

Step-by-step explanation:

Given polynomial expression is $\frac{63(p^4+5p^3-24p^2)}{9p(p+8)}$

To simplify  the given polynomial by dividing the polynomials :

• Now solving the given expression by dividing or factorisation method
• $\frac{63(p^4+5p^3-24p^2)}{9p(p+8)}$
• $=\frac{63p^2(p^2+5p-24)}{9p(p+8)}$

• $=\frac{7p^2.p^{-1}(p^2+5p-24)}{(p+8)}$ ( by using the identity $\frac{1}{a^m}=a^{-m}$ )

• $=\frac{7p^{2-1}(p^2+5p-24)}{(p+8)}$ ( by using the identity $a^m.a^{-n}=a^{m-n}$ )

• $=\frac{7p^{1}(p^2+5p-24)}{(p+8)}$
• $=\frac{7p(p+8)(p-3)}{(p+8)}$ ( split the quadratic into factors )
• $=7p(p-3)$ ( simplifying the factors )
• Therefore $\frac{63(p^4+5p^3-24p^2)}{9p(p+8)}=7p(p-3)$
• Therefore the simplfied expression is 7p(p-3)

Therefore the quotient for the given polyomial is 7p(p-3)