Math, asked by Anonymous, 4 months ago

Divide 64(6a⁴+a²y-15y²) by 4[(2a²/3y)-1]
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Answers

Answered by AshbinMathew
0

Answer:

Carry out the following divisions.

(i) 28x4 ÷ 56x

(ii) –36y³ ÷ 9y²

(iii) 66pq²r3 ÷ 11qr²

(iv) 34x3y3z3 ÷ 51xy²z3

(v) 12a8b8 ÷ (– 6a6b4)

Answer:

1) 28x4 ÷ 56x

= (2×2×7×x×x3 ) /( 2×2×2×7×x)

=x3/2

2) –36y³ ÷ 9y²

= (-2×2×3×3×y×y2 ) /( 3×3×y2)

=-4y

3) 66pq²r3 ÷ 11qr²

= 6pqr

4) 34x3y3z3 ÷ 51xy²z3

=(2/3) x2y

5) 12a8b8 ÷ (– 6a6b4)

=-2a²b4

Question 2

Divide the given polynomial by the given monomial.

(i) (5x² – 6x) ÷ 3x

(ii) (3y8 – 4y6 + 5y4) ÷ y4

(iii) 8(x3y²z² + x²y3z² + x²y²z3) ÷ 4x²y²z²

(iv) (x3 + 2x² + 3x) ÷ 2x

(v) (p3q6 – p6q3) ÷ p3q3

Answer:

(5x² – 6x) ÷ 3x =[x(5x-6)] / 3x

Cancelling x

=(5x-6)/3

(3y8 – 4y6 + 5y4) ÷ y4 = y4(3y4 -4y2 +5)/ y4

=3y4-4y²+5

8(x3y²z² + x²y3z² + x²y²z3) ÷ 4x²y²z² =8x2 y²z²(x+y+z)/ 4x²y²z²

= 2(x+y+z)

(x3 + 2x² + 3x) ÷ 2x =x(x2 +2x+3)/2x

=( x2 +2x+3)/2

(p3q6 – p6q3) ÷ p3q3 = p3 q3(q3 - p3) / p3q3

=(q3 - p3)

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