Question

Divide 64 between A and B such that 3 times A's
share is greater than 4 times B's share by 10.

Answer 1

Answer:   So the two parts of 64 will be 38 and 26  

Step-by-step explanation:

Alright, lets get started.

Suppose 64 is divided into two parts A and B.

So the sum of A and B will be 64

$A+B=64$   ........................... (1)

3 times A's share is greater than 4 times B's share by 10

$3A=4B+10$ ...........................(2)

If we multiply 3 in equation (1), that equation will become

$3A+3B=3 \times64$

$3A+3B=192$  ........................(3)

Putting the value of 3A from equation (2) into equation (3)

$4B+10+3B=192$

$7B=182$

$B=26$

Plugging the value of B in equation (1)

$A+26=64$

$A=38$

So the two parts of 64 will be 38 and 26     :   Answer

Hope it will help :)