Question

Divide 64 in 2 parts so that one part is three times the other part .​

Answer 1

Answer:

Let one part be x.

Other part=3x

3x+x=64

4x=64

x=64/4

x=16

Step-by-step explanation:

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Answer 2

$\star \; {\underline{\boxed{\pmb{\orange{\frak{ \; Given \; :- }}}}}}$

• Given No. = 64
• Second part is three times the First part .

$\star \; {\underline{\boxed{\pmb{\green{\frak{ \; To \; Find \; :- }}}}}}$

• First part = ?
• Second part = ?

$\star \; {\underline{\boxed{\pmb{\pink{\frak{ \; SolutioN \; :- }}}}}}$

$\bigstar$ According to the Question :

$\longmapsto$ Let the First part be y .So,

$\qquad \; {\pmb{\sf{ First \; Part = y }}}$

$\longmapsto$ Second part is 3 times the first part .So,

$\qquad \; {\pmb{\sf{ Second \; Part = 3y }}}$

$\\ \qquad{\rule{150pt}{2pt}}$

$\bigstar$ Calculating the Value of y :

${\longmapsto{\qquad{\sf{ \bigg\{ First \; Part \bigg\} + \bigg\{ Second \; Part \bigg\} = 64 }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ y + 3y = 64 }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ 4y = 64 }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ y = \dfrac{64}{4} }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ y = \cancel\dfrac{64}{4} }}}} \\ \\ \\ \ {\qquad \; \; {\therefore \; {\underline{\boxed{\purple{\pmb{\frak{ y = 16 }}}}}}}}$

$\\ \qquad{\rule{150pt}{2pt}}$

$\bigstar$ Calculating the Two parts :

• First Part = y = 16
• Second Part = 3y = 3(16) = 48

$\\ \qquad{\rule{150pt}{2pt}}$

$\bigstar$ Therefore :

The two parts of the no. are 16 and 48 .

$\\ {\underline{\rule{300pt}{9pt}}}$