Divide 66 into three parts such that sum of first two parts equals the third part
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x=15 then y= 18
x=16 then y= 17
x=14 then y= 19.
and so on....
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Answer:
the value of the first two parts combined, and the third part is 33 each.
Given:
a number, 66
To find:
Divide 66 into three parts such that the sum of the first two parts equals the third part
Solution:
let the three parts be x, y, and z
according to the question,
x +y +z = 66----------[i]
x + y = z-----------[ii]
substitutung [ii] in [i],
z + z = 66
2z = 66
z = 66/2 = 33
x+ y = z
so, x+ y = 33
Hence, the value of the first two parts combined, and the third part is 33 each.
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