Math, asked by gargisoni811, 1 month ago

divide- 6a²b²-3abc+9abd÷-1/3ab

Answers

Answered by jalakpanchal37

2

Answer:

18+9c−27cd

−31ab6ab−3abc+9abcd

By separating denominators, we get

=−31ab6ab+−31ab(−3abc)+−31ab9abcd

=ab6ab×(−3)+ab(−3abc)×(−3)+ab(9abcd)×(−3)

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