Math, asked by snehalgharat101, 1 day ago

divide 6x^2 +8x +2 by 3x+1

Answers

Answered by manoj939265
0

Answer:

(3x² - 4x - 1)

x-1

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Answered by nitikabisht100
2

(((6 • (x3)) - 23x2) + 3x) - 1 = 0

((2•3x3) - 23x2) + 3x) - 1 = 0

6x3-8x2+3x-1 is not a perfect cube

Factoring: 6x3-8x2+3x-1

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: 3x-1

Group 2: 6x3-8x2

Pull out from each group separately :

Group 1: (3x-1) • (1)

Group 2: (3x-4) • (2x2)

Find roots (zeroes) of : F(x) = 6x3-8x2+3x-1

Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0

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