Math, asked by Damapooja555, 9 months ago

divide 6x^3-x^2+9x+2 by (2x+1) and verify the division rule

Answers

Answered by darshit5348
1

Answer:

your questions is wrong

Answered by AadilPradhan
5

Answer:

Quotient Q(x) = 3x2 - 2x + 5

Remainder R(x) = x - 3

Step-by-step explanation:

When 6x3 - x2 + 9x + 2 is divided by 2x + 1 we will get the quotient Q(x) as 3x2 - 2x + 5 and remainder R(x) as x - 3.

The long division method is attached with the answer. Please refer to it for better understanding.

Verification :-

We know that,

Dividend D(x) = divisor d(x) * Quotient Q(x) + Remainder R(x)

6x3 - x2 + 9x + 2

= (3x2 - 2x + 5) * (2x + 1) + (x - 3)

= (6x3 + 3x2 - 4x2 - 2x + 10x + 5 + x - 3)

= 6x3 - x2 + 9x + 2

Since, L.H.S. = R.H.S.

Hence Verified.

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