Question

. Divide 6x2-13x+6 by 2x–3.​

Answer 1

Step-by-step explanation:

6−13x+6x

2

=6−9x−4x+6x

2

=3(2−3x)−2x(2−3x)

=(2−3x)(3−2x)

Divide by −3+2x

=

−(3+2x)

(2−3x)(3−2x)

=−2+3x=3x−2

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Answer 2

The answer is 3x-2.

Given :

To divide 6x²-13x+6  by 2x-3

To find :

The value of  $\frac{6x^{2} -13x+6}{2x-3}$

Solution :

The polynomial equation 6x²-13x+6 can be written as,

                      6x²-13x+6 = 6-9x-4x+6x²

                                        = 3(2-3x)-2x(2-3x)

                                        = (2-3x) (3-2x)

Now divide it by 2x-3,

                          $\frac{6x^{2} -13x+6}{2x-3}$    =  $\frac{(2-3x) (3-2x)}{2x-3}$

                                             = $\frac{-(2-3x) (3-2x)}{2x-3}$

                                             =  3x-2

Therefore, The value of   $\frac{6x^{2} -13x+6}{2x-3}$ is 3x-2

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