Math, asked by harini330, 2 months ago

Divide 6x²+24x+18(x+3)

Answers

Answered by Virensangwan0123
1

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "x2" was replaced by "x^2".

Step by step solution :

STEP

1

:

Equation at the end of step 1

((2•3x2) - 24x) + 18 = 0

STEP

2

:

STEP

3

:

Pulling out like terms

3.1 Pull out like factors :

6x2 - 24x + 18 = 6 • (x2 - 4x + 3)

Trying to factor by splitting the middle term

3.2 Factoring x2 - 4x + 3

The first term is, x2 its coefficient is 1 .

The middle term is, -4x its coefficient is -4 .

The last term, "the constant", is +3

Step-1 : Multiply the coefficient of the first term by the constant 1 • 3 = 3

Step-2 : Find two factors of 3 whose sum equals the coefficient of the middle term, which is -4 .

-3 + -1 = -4 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -3 and -1

x2 - 3x - 1x - 3

Step-4 : Add up the first 2 terms, pulling out like factors :

x • (x-3)

Add up the last 2 terms, pulling out common factors :

1 • (x-3)

Step-5 : Add up the four terms of step 4 :

(x-1) • (x-3)

Which is the desired factorization

Equation at the end of step

3

:

6 • (x - 1) • (x - 3) = 0

STEP

4

:

Theory - Roots of a product

4.1 A product of several terms equals zero.

When a product of two or more terms equals zero, then at least one of the terms must be zero.

We shall now solve each term = 0 separately

In other words, we are going to solve as many equations as there are terms in the product

Any solution of term = 0 solves product = 0 as well.

Equations which are never true:

4.2 Solve : 6 = 0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation:

4.3 Solve : x-1 = 0

Add 1 to both sides of the equation :

x = 1

Solving a Single Variable Equation:

4.4 Solve : x-3 = 0

Add 3 to both sides of the equation :

x = 3

Supplement : Solving Quadratic Equation Directly

Solving x2-4x+3 = 0 directly

Earlier we factored this polynomial by splitting the middle term. let us now solve the equation by Completing The Square and by using the Quadratic Formula

Parabola, Finding the Vertex:

5.1 Find the Vertex of y = x2-4x+3

Parabolas have a highest or a lowest point called the Vertex . Our parabola opens up and accordingly has a lowest point (AKA absolute minimum) . We know this even before plotting "y" because the coefficient of the first term, 1 , is positive (greater than zero).

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