Question

divide 6x³+x²-26x-21 by 3x-7 and verify division algorithm​

Answer 1

Answer:

division algorithm-

D = d×Q +R

(dividend = divisor × quotient +remainder)

divisor = 3x-7

quotient = 2x² +5x+3

dividend = 6x³ +x²-26x-21

remainder = 0

D = (3x-7)(2x²+5x+3)+0

D = 3x(2x²+5x+3)-7(2x²+5x+3)

= 6x³+15x²+9x-14x²-35x-21

= 6x³ +x²-26x-21

6x³ +x²-26x-21 = 6x³ +x²-26x-21

L.H.S = R.H.S

hence verified.

* Note - For division refer the attachment.

Answer 2

Answer :

Quotient = 2x^2 + 5x + 3

Remainder = 0

Step-by-step explanation:

NOTE : THE CLEAR EXPLANATION OF THIS QUESTION ALONG WITH VERIFICATION IS GIVEN IN THE ATTACHMENT BELOW.