Math, asked by abhijoysarkhel, 19 days ago

Divide ₹72 between A,B and C so that B may have ₹8 more than A and C may have ₹2 more than B​

Answers

Answered by sankhadeepbhadra7
0

Answer:

A=18

B=26

C=28

This the correct answer

Answered by rajesh9040957822
0

Answer:

if A has x

then B has x+8

C has x+8+2=x+10

Total money is 72

x+x+8+x+10=72

3x+18=72

3x=72-18=54

x=54/3

x=18

So A=18

B=x+8=18+8=26

C=x+10=18+10=28 (Ans)

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