Divide 72 into two parts so that the larger part exceed the smaller part by 12. Find both the part
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Answer:
30 &42 THEIR SOME Is 72 and difference between them is 12
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Answer:
let the numbers be x and x+12
x × x+12 =72
×^2 +12=72
×^2=72-12
x^2=60
x = 60÷2= 30
x= 30
x+12=42
THE REQUIRED NUMBERS ARE 30 AND 42 RESPECTIVELY.
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