Question

Divide 72 into two parts so that the larger part exceeds the smaller part by 12. Find both the parts

Answer 1

Let the two digits which 72 is divided =  x and (72 -x)

Also, let the larger part be x
The larger part exceeds the smaller part by 12
Therefore 
x - (72 - x) = 12
x - 72 + x = 12
2x = 84
x = 42
one number is 42
another number is (72 - x) = 30
The numbers are 30 and 42.

Answer 2

Let x be the smaller part.

Then according to question,

x + (x+12) = 72

x + x + 12 = 72

    2x + 12 = 72

            2x = 72 - 12

              x = 60/2

              x = 30

Then the smaller part = x = 30

                larger part   = x + 12 = 30 +12 = 42

Hence the parts are 30 and 42 that makes up 72 (according to ques).
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