Question

DIVIDE 72 INTO TWO PARTS SO THAT THE LARGER PART EXCEEDS THE SMALLER PART BY 12. FIND BOTH THE PART.

Answer 1

Pls Mark as the BRAINLIEST

Step-by-step explanation:

Let the two numbers be x and y.

Let the two numbers be x and y.The larger part exceeds the smaller part by 12.

Let the two numbers be x and y.The larger part exceeds the smaller part by 12.x=y+12

Let the two numbers be x and y.The larger part exceeds the smaller part by 12.x=y+12x+y=72

Let the two numbers be x and y.The larger part exceeds the smaller part by 12.x=y+12x+y=72y+12+y=72

Let the two numbers be x and y.The larger part exceeds the smaller part by 12.x=y+12x+y=72y+12+y=722y=72-12

Let the two numbers be x and y.The larger part exceeds the smaller part by 12.x=y+12x+y=72y+12+y=722y=72-122y=60

Let the two numbers be x and y.The larger part exceeds the smaller part by 12.x=y+12x+y=72y+12+y=722y=72-122y=60y=60/2

Let the two numbers be x and y.The larger part exceeds the smaller part by 12.x=y+12x+y=72y+12+y=722y=72-122y=60y=60/2y=30

Let the two numbers be x and y.The larger part exceeds the smaller part by 12.x=y+12x+y=72y+12+y=722y=72-122y=60y=60/2y=30x=30+12

Let the two numbers be x and y.The larger part exceeds the smaller part by 12.x=y+12x+y=72y+12+y=722y=72-122y=60y=60/2y=30x=30+12x=42

Answer 2

Step-by-step explanation:

Let us assume smaller part as x

So, the larger part will be x+12, as it exceeds by 12

So,

x+ x+12 =72(as the sum will be 72)

2x+12=72

2x= 72-12

2x=60

x= 60/2

x=30, x+12 =30+12= 42(easy method)

Verification:

30+42 =72.

Hope this helps you!!!

Please mark my answer as brainliest answer as no one is marking it!!!