Question

divide 740 rupees in the ratio 5:4​

Answer 1

Explanation:

FIRST METHOD:-

given

X+Y= 740...............(1)

X/Y= 5/4

=> 4X-5Y= 0................(2)

(1)×4 - (2)

9Y= 740×4

Y= 740×4/9= 328 integer 8/9

substituting in (1)

X+328+8/9= 740

X= 740-328-8/9

X= 412-8/9

X= 411 integer 1/9

therefore the numbers are

411 integer 1/9 and 328 integer 8/9

METHOD 2:-

first no= sum×ratio of first/sum of ratio

= 740×5/9= 411 integer 1/9

second number= sum×ratio of 2nd/sum of ratio

= 740×4/9= 328 integer 8/9