divide 75 into two parts so that one part is less than other by 13
Answers
Answered by
13
let i part be x
so second part=75-x
atq-
x- (75-x)=13
x-75+x=13
2x=13+75
x=88/2=44
1 part=44 second=75-44=31
so second part=75-x
atq-
x- (75-x)=13
x-75+x=13
2x=13+75
x=88/2=44
1 part=44 second=75-44=31
Answered by
1
The two numbers satisfying this condition are 44 and 31.
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