Question

divide ₹760 among A,B,C such B gets three times as much as A gets and C gets half of as much as B gets?​

Answer 1

Step-by-step explanation:

Let B gets ₹ x

$\because$ B gets three times as much as A.

$\therefore$ A gets one third of B

$\therefore A\: gets \frac{1}{3}x\\</p><p>\& C gets \frac{1}{2}x$

Now,

A + B + C = ₹ 760

$\therefore \frac{1}{3}x + x +\frac{1}{2}x=760\\</p><p> \implies \frac{2}{6}x + \frac{6}{6}x +\frac{3}{6}x=760\\ </p><p> \implies \frac{2+6+3}{6}x =760\\ </p><p> \implies \frac{11}{6}x =760\\ </p><p> \implies =760 \times\frac{6}{11} \\ </p><p> \implies x = \frac{760 \times 6}{11} \\ </p><p> \implies x = \frac{4560}{11} \\</p><p>\implies x = \frac{4560}{11} \\</p><p>\implies x = \frac{4560}{11} \\</p><p>\frac{1}{3}x= \frac{4560}{11\times 3} == \frac{4560}{33}</p><p>\\</p><p>\frac{1}{2}x= \frac{4560}{11\times 2} == \frac{4560}{22}$

Answer 2

Answer:

A=138.18, B=414.56, C=207.26

Step-by-step explanation:

B=3A => A=B/3

C=1/2(B) => C=B/2

A + B + C = 760

B/3 + B + B/2= 760

11B/6 = 760

B = 4560/11

B = 414.56

A = B/3 => 414.56/3 => 138.18

C = B/2 => 414.56/2 => 207.26

u can verify by substituting the values in A+B+C=760

where u will get       760=760

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