Question

divide (7z2-112) by 7(z+4)

Answer 1

(7z²-112)/7(z+4)

7(z²-16)/7(z+4)

z²-16/z+4

z²-(4)²/z+4

using a²-b²=(a+b)(a-b)

(z+4)(z-4)/z+4

=>(z-4)/1
=>(z-4)



hope this helps you...