Math, asked by kritikayadav5422, 2 months ago

divide (8+19x+x^2-6x^3)by (92+5x-3x) and verify division algorithm​

Answers

Answered by santwanamohanty3
0

Step-by-step explanation:

          2x   +   3

                              -----------------------------------------

- 3x^2  +  5x  + 2)  -6x^3  +  x^2   +   19x   +   8

                             -6x^3   + 10x^2  +  4x

                            ----------------------------------------------

                                             -9x^2  +  15x  +   8

                                             - 9x^2  +  15x  +  6

                           ---------------------------------------------------

                                                                       2.

Now,

Quotient = 2x + 3, Remainder = 2, Dividend = -6x^3 + x^2 + 19x + 8, Divisor = -3x^2 + 5x + 2.

Divisor * Quotient +  Remainder.

(-3x^2 + 5x + 2) * (2x + 3) + 2

-6x^3 + x^2 + 19x + 6 + 2

-6x^3 + x^2 + 19x + 8.

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