divide 8 into two parts such that the sum of their squares is 34
Answers
Answered by
3
The numbers are 5 & 3
solankitapasya:
plz mark as brainliest
Answered by
46
Let One Part Of The Number be x so other part = (8 - x)
According to given statement
x² + (8 - x)² = 34
x² + 64 + x² - 16x = 34
2x² - 16x + 64 - 34 = 0
2x² - 16x + 30 = 0
2x² - 6x - 10x + 30 = 0
2x(x - 3) -10(x - 3) = 0
(2x - 10)(x - 3) = 0
x = 10/2 OR x = 3
x = 5 OR x = 3
If x is 5 other number = 3
If x is 3 other number = 5
Mark This Brainliest If This Helped You
According to given statement
x² + (8 - x)² = 34
x² + 64 + x² - 16x = 34
2x² - 16x + 64 - 34 = 0
2x² - 16x + 30 = 0
2x² - 6x - 10x + 30 = 0
2x(x - 3) -10(x - 3) = 0
(2x - 10)(x - 3) = 0
x = 10/2 OR x = 3
x = 5 OR x = 3
If x is 5 other number = 3
If x is 3 other number = 5
Mark This Brainliest If This Helped You
Similar questions