Question

divide 80 into two parts so that the greater part is 4 times the smaller part

Answer 1

Let the parts be x and y.

Given that x + y = 80 and x = 4y.

                  4y + y = 80

                     5y = 80

                      y = 16.

x = 4y

   = 4 * 16

  = 64.

The values are 16,64.