Question

Divide 80 mangoes between x and y so that x get 14 mangoes more than y

Answer 1

$\huge\mathcal{Heya}$

Given :-

Total mangoes = 80

Solution :-

Let,

No. of mangoes with x = a

And

No. of mangoes with y = b

So,

a + b = 80 ________(1)

Also,

a = b + 14 __________(2)

Putting (2) in (1), we get

b + 14 + b = 80

2b + 14 = 80

b = 33

Put this in eq(1)

a + 33 = 80

a = 47

Hence,

Mangoes with x = 47

Mangoes with y = 33

$\huge\mathbb{Hope \ this \ helps.}$

Answer 2

Suppose that X have a mangoes & Y have b mangoes

X get 14 mangoes more than Y

a-b=14.. Equation(1)

Total mangoes = 80

a+b=80...Equation(2)

Take sume eq(1) & Eq(2)

2a= 94

a=47 so b=33