Divide 804 among A, B, and C so that B may get twice and C may get thrice as much as A
Answers
Answered by
0
a+2a+3a=804
a=134
b=2a=268
c=3a=402
a=134
b=2a=268
c=3a=402
Answered by
5
let the A = x
let B = 2x
and let C = 3x
than, 3x + 2x + x = 804
6x = 804
x = 134
Now A get 134 , B get 268 and c get 402
hope it helps you
( mark me as brainliest )
let B = 2x
and let C = 3x
than, 3x + 2x + x = 804
6x = 804
x = 134
Now A get 134 , B get 268 and c get 402
hope it helps you
( mark me as brainliest )
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