Math, asked by martinagonu993, 1 year ago

Divide 804 among A, B and C so that B may get twice and C may get thrice as much as A

Answers

Answered by Hiteshbehera74

0

As per given condition,

B=2C & C=3A.

Given,

A+B+C = 804

A+2C+C = 804

A+6A+3A = 804

10A = 804

A = 80.4

Hence,

C = 3A = 3(80.4) = 241.2

B = 2C = 2(241.2) = 482.4

A = 80.4

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