Question

divide 820 into two parts such that 30% of one part exceeds 40% of the other by 50

Answer 1

Answer:

Let we divide 820 in X and Y part

ATQ

X+Y=820. (1)

and

3X/10=50+4Y/10

3X-4Y=500

from 1, X=820-Y

3(820-Y)-4Y=500

2460-3Y-4Y=500

1960=7Y

Y=280

X=520