Question

Divide 84 into two parts such that 1/4 of one part is equal to 1/3 of the other part

Answer 1

let it divided in x
so other part become 84-x
ATQ
1/4(x)=1/3(84-x)
x/4 = 28 -x/3
x/4+x/3 =28
7x /12=28
x=28×12/7=48 =FIRST PART
SECOND PART=84-48 = 36

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Answer 2

Answer:

Required first part is 48 and second part is 36.

Step-by-step explanation:

Here we want to divide 84 into two parts.

Let amount of first part be x and amount of second part be (84-x)

It is also given,1/4 of one part is equal to 1/3 of the other part.

So according to question,

$\frac{1}{4} \times x = \frac{1}{3} (84 - x) \\ \frac{x}{4} = \frac{84}{3} - \frac{x}{3} \\ \frac{x}{4} + \frac{x}{3} = \frac{84}{3} \\ \frac{3x + 4x}{12} = 28 \\ \frac{7x}{12} = 28 \\ x = 28 \times \frac{12}{7} \\ x = 4 \times 12 \\ x = 48$

Therefore first part is 48 and second part is (84-48) = 36.

This is a problem of Algebra.

Some important Algebra formulas.

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Know more about Algebra,

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

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