Question

divide 84 into two parts such that half of its first part is 4 less than the half part of other part.​

Answer 1

Answer:

the no.s are 40 and 44

Step-by-step explanation:

let the no.s be x and y

according to question the first half is 4 less than the other half. then the difference of the digit will be equal to 4

so, x-y=4 _____ eq1

and if two digit are divide in two parts then there sum will b equal to 84

x+y=10 _______eq2

from eq 1 value of x = 4+y.

put value of x in eq 1

(4+y)+y=84

4×2y=84

y= 40

we know x+y=84

x+40=84

x=44