Math, asked by Zafar3127, 1 year ago

Divide 84 into two parts such that half of the first part is 4 less than the half of the other part

Answers

Answered by TheNightHowler
2
Let 2 parts be x and (84-x)

ATQ: x/2 = (84-x)/2-4

=> 4*2 = (84-x-2)
=> x= 82-8
=> x = 74
Parts: 74 and 10
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