Math, asked by sridevik, 2 months ago

Divide: 8a^2b^3 + 4a^2b + 6a^3b + 10ab^2 by (2ab)
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Answers

Answered by bagkakali
1

Answer:

(8a^2b^3+4a^2b+6a^3b+10ab^2)÷2ab

=8a^2b^3/2ab+4a^2b/2ab+6a^3b/2ab

+10ab^2/2ab

=4ab^2+2a+3a^2+5b

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