Question

divide 8a² + 16a⁴ -12a³ by 4a²​

Answer 1

ANSWER:

$\sf \large \frac{8a {}^{2} + 16 {a}^{4} - 12 {a}^{3} }{4 {a}^{2} }$

Now take 4a² common from numerator.

$\sf \large\frac{ \cancel{4 {a}^{2}}(2 + 4 {a}^{2} - 3a) }{ \cancel{4 {a}^{2} }}$

$\sf \large2 + 4 { a }^{2} - 3a$

This is the final answer.