Question

divide (-8x ^3 - 27) by (2x - 3)
Please answer practically...​

Answer 1

Answer:

8x3−272x−38x3-272x-3

Simplify the numerator.

Tap for fewer steps...

Rewrite 8x38x3 as (2x)3(2x)3.

(2x)3−272x−3(2x)3-272x-3

Rewrite 2727 as 3333.

(2x)3−332x−3(2x)3-332x-3

Since both terms are perfect cubes, factor using the difference of cubes formula, a3−b3=(a−b)(a2+ab+b2)a3-b3=(a-b)(a2+ab+b2) where a=2xa=2x and b=3b=3.

(2x−3)((2x)2+2x⋅3+32)2x−3(2x-3)((2x)2+2x⋅3+32)2x-3

Simplify.

(2x−3)(4x2+6x+9)2x−3(2x-3)(4x2+6x+9)2x-3

Cancel the common factor of 2x−32x-3.

Cancel the common factor.

(2x−3)(4x2+6x+9)2x−3(2x-3)(4x2+6x+9)2x-3

Divide 4x

Step-by-step explanation:

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