divide (8x²+6x-35) by (4x-7)
Answers
Answer:
Step-by-step explanation:
STEP 1 : Equation at the end of step 1
STEP 2 : 8x2 + 6x - 35
Simplify —————————————
4x - 7
Step 3 : Trying to factor by splitting the middle term
Factoring 8x2 + 6x - 35
The first term is, 8x2 its coefficient is 8 .
The middle term is, +6x its coefficient is 6 .
The last term, "the constant", is -35
(Step-1 ): Multiply the coefficient of the first term by the constant 8 • -35 = -280
(Step-2) : Find two factors of -280 whose sum equals the coefficient of the middle term, which is 6 .
-280 + 1 = -279
-140 + 2 = -138
-70 + 4 = -66
-56 + 5 = -51
-40 + 7 = -33
-35 + 8 = -27
-28 + 10 = -18
-20 + 14 = -6
-14 + 20 = 6 That's it
(Step-3) : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -14 and 20
8x2 - 14x + 20x - 35
(Step-4) : Add up the first 2 terms, pulling out like factors :
2x • (4x-7)
Add up the last 2 terms, pulling out common factors :
5 • (4x-7)
(Step-5) : Add up the four terms of step 4 :
(2x+5) • (4x-7)
Which is the desired factorization
Canceling Out : Cancel out (4x-7) which appears on both sides of the fraction line.
Final result : 2x + 5
munishsharma32
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