Question

divide 8x²+6x³+12x by 2x​

Answer 1

Answer:

Divide the polynomial 6x³ + 8x² by the monomial 2x. What is the quotient and remainder?

numerator =

\begin{gathered}6 {x}^{3} + 8 {x}^{2} \\ \\ = 2 {x}^{2} \times 3x + 2 {x}^{2} \times 4 \\ \\ = 2 {x}^{2} (3x + 4) \\ \\ = 2x \times x \times (3x + 4)\end{gathered}

6x

3

+8x

2

=2x

2

×3x+2x

2

×4

=2x

2

(3x+4)

=2x×x×(3x+4)

Denominator = 2x

cancelling 2x from numerator and denominator

= x (3x +4)

quotient = x (3x +4)

= 3 {x}^{2} + 4x=3x

2

+4x

remainder = 0

Answer 2

Answer:

3x^2 + 4x + 6

Step-by-step explanation:

just divide using division algorithm. you will get the answer easily