Question

Divide
8x³-12x²-14x+21 by 2x-3​

Answer 1

Step-by-step explanation:

quotient=4x^2-7

remainder=0

HOPE IT HELPS!

Answer 2

Answer:

The value of $\frac{8x^{3}-12x^{2} -14x+21 }{2x-3}$ is $(4x^{2} -7)$.

Step-by-step explanation:

Given : $\frac{8x^{3}-12x^{2} -14x+21 }{2x-3}$

To find : The value of the above expression.

Solution :

• The given expression is $\frac{8x^{3}-12x^{2} -14x+21 }{2x-3}$.
• We have to simplify the above expression.
• The given equation is,

     $\frac{8x^{3}-12x^{2} -14x+21 }{2x-3}$ $= \frac{4x^{2} (2x-3)-7(2x-3)}{2x-3}$  

(∵ Taking out common terms from the numerator)

                     $= \frac{(4x^{2} -7)(2x-3)}{(2x-3)}$

                     $= 4x^{2} -7$

• ∴ The value of $\frac{8x^{3}-12x^{2} -14x+21 }{2x-3}$ is $(4x^{2} -7)$.